3x^2=448

Solution for 3x^2=448 equation:

3x^2=448

We move all terms to the left:

3x^2-(448)=0

a = 3; b = 0; c = -448;
Δ = b2-4ac
Δ = 02-4·3·(-448)
Δ = 5376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5376}=\sqrt{256*21}=\sqrt{256}*\sqrt{21}=16\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{21}}{2*3}=\frac{0-16\sqrt{21}}{6}
=-\frac{16\sqrt{21}}{6}
=-\frac{8\sqrt{21}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{21}}{2*3}=\frac{0+16\sqrt{21}}{6}
=\frac{16\sqrt{21}}{6}
=\frac{8\sqrt{21}}{3}
$